Reported Question / Answer
here relation between still and against has given that is 1 & 3 so let assume x is stream speed and also distance is constant so d1 = d2 speed in still * time = sppeed into against stream * time now according to the question speed in still = 3*speed against water 6 = (6-x)3 6= 18- 3x x= 4km/h
Speed of boat in still water = 6 km / hour Let the distance = x km Time taken = x/6 hrs Time is going the same distance against the current = 3x/6=x/2 hrs Let the speed pf the current = y km/hr Speed against the current = 6−y km/hr Time taken for distance x= x/( 6−y) hrs. hence x/2=x/( 6−y) →( 6−y) = 2 and y= 4 km/hr Hence Speed pf the current = y km/hr =4 km/hr
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